2,25y^2-4y-1=0

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Solution for 2,25y^2-4y-1=0 equation: 



2.25y^2-4y-1=0

a = 2.25; b = -4; c = -1;
Δ = b2-4ac
Δ = -42-4·2.25·(-1)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-5}{2*2.25}=\frac{-1}{4.5}
=-1/4.5
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+5}{2*2.25}=\frac{9}{4.5}
=2
$

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